Mathematics · 2026
JEE Main · 21 January 2026, Shift 2 · Q11
Let one end of a focal chord of the parabola y^2=16 x be (16,16). If P (α, β) divides this focal chord internally in the ratio 5: 2, then the minimum…
Let one end of a focal chord of the parabola $\displaystyle y^2=16 x$ be $\displaystyle (16,16)$. If $\displaystyle \mathrm{P}(\alpha, \beta)$ divides this focal chord internally in the ratio $\displaystyle 5$ : $\displaystyle 2$, then the minimum value of $\displaystyle \alpha+\beta$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 7$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.