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Mathematics · 2021

JEE Main · 27 July 2021, Shift 2 · Q83

Let n be a non-negative integer. Then the number of divisors of the form " 4 n +1 " of the number (10)^10 ·(11)^11 ·(13)^13 is equal to \ \ \ \.

Let n be a non-negative integer. Then the number of divisors of the form " $\displaystyle 4 \mathrm{n}+1$ " of the number $\displaystyle (10)^{10} \cdot(11)^{11} \cdot(13)^{13}$ is equal to \_\_\_\_.
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