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Mathematics · 2024

JEE Main · 6 April 2024, Shift 1 · Q7

Let A={n ∈[100,700] ∩ N: n is neither a multiple of 3 nor a multiple of 4 }. Then the number of elements in A is

Let $\displaystyle A=\{n \in[100,700] \cap \mathbb{N}: n$ is neither a multiple of $\displaystyle 3$ nor a multiple of $\displaystyle 4 \}$. Then the number of elements $\displaystyle \operatorname{in} A$ is
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.