Mathematics · 2021
JEE Main · 18 March 2021, Shift 2 · Q65
Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively.…
Let in a Binomial distribution, consisting of $\displaystyle 5$ independent trials, probabilities of exactly $\displaystyle 1$ and $\displaystyle 2$ successes be $\displaystyle 0.4096$ and $\displaystyle 0.2048$ respectively. Then the probability of getting exactly $\displaystyle 3$ successes is equal to :
Official answer
(4)
$\displaystyle \frac{32}{625}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.