Mathematics · 2026
JEE Main · 23 January 2026, Shift 1 · Q18
Let f(x)=∫ ((2-x^2) · e^x)/((√(1+x))(1-x)^3 / 2) d x. If f(0)=0, then f(1/2) is equal to:
Let $\displaystyle f(x)=\int \frac{\left(2-x^2\right) \cdot \mathrm{e}^x}{(\sqrt{1+x})(1-x)^{3 / 2}} \mathrm{~d} x$. If $\displaystyle f(0)=0$, then $\displaystyle f\left(\frac{1}{2}\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \sqrt{3 \mathrm{e}}-1$
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