Mathematics · 2022
JEE Main · 27 July 2022, Shift 2 · Q4
Let A= (4, -2; α, β). If A^2+γ A +18 I = O, then det ( A ) is equal to \ \ \ \.
Let $\displaystyle A=\left(\begin{array}{rr}4 & -2 \\ \alpha & \beta\end{array}\right)$.
If $\displaystyle \mathrm{A}^2+\gamma \mathrm{A}+18 \mathrm{I}=\mathrm{O}$, then $\displaystyle \operatorname{det}(\mathrm{A})$ is equal to \_\_\_\_.
Official answer
(2)
$\displaystyle 18$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.