Mathematics · 2020
JEE Main · 9 January 2020, Shift 2 · Q54
Let a-2 b+c=1. If f(x)= |x+ a, x+2, x+1; x+ b, x+3, x+2; x+ c, x+4, x+3|, then:
Let $\displaystyle a-2 b+c=1$.
If $\displaystyle f(x)=\left|\begin{array}{ccc}x+\mathrm{a} & x+2 & x+1 \\ x+\mathrm{b} & x+3 & x+2 \\ x+\mathrm{c} & x+4 & x+3\end{array}\right|$, then :
Official answer
(3)
$\displaystyle f(50)=1$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.