Mathematics · 2022
JEE Main · 26 June 2022, Shift 2 · Q5
Let f(x)= min {1,1+x sin x}, 0 ≤ x ≤ 2 π. If m is the number of points, where f is not differentiable and n is the number of points, where f is not…
Let $\displaystyle f(x)=\min \{1,1+x \sin x\}, 0 \leq x \leq 2 \pi$. If $\displaystyle m$ is the number of points, where $\displaystyle f$ is not differentiable and $\displaystyle n$ is the number of points, where $\displaystyle f$ is not continuous, then the ordered pair $\displaystyle (m, n)$ is equal to
Official answer
(2)
$\displaystyle (1,0)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.