Mathematics · 2021
JEE Main · 26 August 2021, Shift 2 · Q76
Let [ t ] denote the greatest integer less than or equal to t. Let f(x)=x-[x], g(x)=1-x+[x], and h (x)= min {f(x), g(x)}, x ∈[-2,2]. Then h is:
Let $\displaystyle [\mathrm{t}]$ denote the greatest integer less than or equal to t .
Let $\displaystyle f(x)=x-[x], g(x)=1-x+[x]$, and $\displaystyle \mathrm{h}(x)=\min \{f(x), g(x)\}, x \in[-2,2]$.
Then h is :
Official answer
(3)
continuous in [-$\displaystyle 2$, $\displaystyle 2$] but not differentiable at more than four points in $\displaystyle (-2, 2)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.