Mathematics · 2024
JEE Main · 8 April 2024, Shift 1 · Q13
Let y=y(x) be the solution of the differential equation (1+y^2) e^tan x d x+ cos^2 x(1+e^2 tan x) d y=0, y(0)=1. Then y((π)/4) is equal to
Let $\displaystyle y=y(x)$ be the solution of the differential equation
$\displaystyle \left(1+y^2\right) e^{\tan x} d x+\cos ^2 x\left(1+e^{2 \tan x}\right) d y=0, y(0)=1$. Then $\displaystyle y\left(\frac{\pi}{4}\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{1}{e}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.