Let y=y(x) be the solution of the differential equation x^3 d y+(x y-1) d x=0, x>0, y(1/2)=3- e. Then y (1) is equal to

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x^3 d y+(x y-1) d x=0, x>0$, $\displaystyle y\left(\frac{1}{2}\right)=3-\mathrm{e}$. Then $\displaystyle \mathrm{y}(1)$ is equal to