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Mathematics · 2023

JEE Main · 11 April 2023, Shift 2 · Q13

Let y=y(x) be the solution of the differential equation (d y)/(d x)+5/(x(x^5+1)) y=((x^5+1)^2)/x^7, x>0. If y(1)=2, then y(2) is equal to

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \frac{d y}{d x}+\frac{5}{x\left(x^5+1\right)} y=\frac{\left(x^5+1\right)^2}{x^7}, x>0$. If $\displaystyle y(1)=2$, then $\displaystyle y(2)$ is equal to
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