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Mathematics · 2024

JEE Main · 9 April 2024, Shift 1 · Q2

Let α, β be the roots of the equation x^2+2 √ 2 x-1=0. The quadratic equation, whose roots are α^4+β^4 and 1/10(α^6+β^6), is:

Let $\displaystyle \alpha, \beta$ be the roots of the equation $\displaystyle x^2+2 \sqrt{2} x-1=0$. The quadratic equation, whose roots are $\displaystyle \alpha^4+\beta^4$ and $\displaystyle \frac{1}{10}\left(\alpha^6+\beta^6\right)$, is :
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.