Mathematics · 2026
JEE Main · 21 January 2026, Shift 2 · Q12
Let y^2=12 x be the parabola with its vertex at O. Let P be a point on the parabola and A be a point on the x -axis such that ∠ OPA =90^°. Then the…
Let $\displaystyle y^2=12 x$ be the parabola with its vertex at O . Let P be a point on the parabola and A be a point on the $\displaystyle x$-axis such that $\displaystyle \angle \mathrm{OPA}=90^{\circ}$. Then the locus of the centroid of such triangles OPA is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle y^2-2 x+8=0$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.