Mathematics · 2023
JEE Main · 8 April 2023, Shift 1 · Q13
Let C(α, β) be the circumcenter of the triangle formed by the lines 4 x+3 y=69, 4 y-3 x=17, and x+7 y=61. Then (α-β)^2+α+β is equal to
Let $\displaystyle C(\alpha, \beta)$ be the circumcenter of the triangle formed by the lines
$$\begin{aligned}
& 4 x+3 y=69, \\
& 4 y-3 x=17, \text { and } \\
& x+7 y=61 .
\end{aligned}
$$
Then $\displaystyle (\alpha-\beta)^2+\alpha+\beta$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 17$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.