Mathematics · 2020
JEE Main · 6 September 2020, Shift 1 · Q66
Let L_1 be a tangent to the parabola y^2=4(x+1) and L_2 be a tangent to the parabola y^2=8(x+2) such that L_1 and L_2 intersect at right angles. Then…
Let $\displaystyle \mathrm{L}_1$ be a tangent to the parabola $\displaystyle y^2=4(x+1)$ and $\displaystyle \mathrm{L}_2$ be a tangent to the parabola $\displaystyle y^2=8(x+2)$ such that $\displaystyle \mathrm{L}_1$ and $\displaystyle \mathrm{L}_2$ intersect at right angles. Then $\displaystyle \mathrm{L}_1$ and $\displaystyle \mathrm{L}_2$ meet on the straight line :
Official answer
(4)
$\displaystyle x+3=0$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.