Mathematics · 2026
JEE Main · 21 January 2026, Shift 1 · Q5
Let a_1, a_2, a_3, … be a G.P. of increasing positive terms such that a_2. a_3. a_4=64 and a_1+ a_3+ a_5=813/7. Then a_3+ a_5+ a_7 is equal to:
Let $\displaystyle \mathrm{a}_1, \mathrm{a}_2, \mathrm{a}_3, \ldots$ be a G.P. of increasing positive terms such that $\displaystyle \mathrm{a}_2 . \mathrm{a}_3 . \mathrm{a}_4=64$ and $\displaystyle \mathrm{a}_1+\mathrm{a}_3+\mathrm{a}_5=\frac{813}{7}$. Then $\displaystyle \mathrm{a}_3+\mathrm{a}_5+\mathrm{a}_7$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3252$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.