Mathematics · 2013
JEE Main · 23 April 2013, Shift 1 · Q81
Let f be a composite function of x defined by f( u )=1/(u^2+ u -2), u (x)=1/(x-1). Then the number of points x where f is discontinuous is:
Let $\displaystyle f$ be a composite function of $\displaystyle x$ defined by $\displaystyle f(\mathrm{u})=\frac{1}{\mathrm{u}^2+\mathrm{u}-2}, \mathrm{u}(x)=\frac{1}{x-1}$.Then the number of points $\displaystyle x$ where $\displaystyle f$ is discontinuous is :
Official answer
(2)
$\displaystyle 3$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.