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Mathematics · 2022

JEE Main · 29 July 2022, Shift 2 · Q28

Let A B be a chord of length 12 of the circle (x-2)^2+(y+1)^2=169/4. If tangents drawn to the circle at points A and B intersect at the point P, then…

Let $\displaystyle A B$ be a chord of length $\displaystyle 12$ of the circle $\displaystyle (x-2)^2+(y+1)^2=\frac{169}{4}$. If tangents drawn to the circle at points $\displaystyle A$ and $\displaystyle B$ intersect at the point $\displaystyle P$, then five times the distance of point $\displaystyle P$ from chord $\displaystyle A B$ is equal to \_\_\_\_.
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.