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Mathematics · 2021

JEE Main · 3 August 2021, Shift 2 · Q90

Let a =2 i +α j + k and b =β i -5 j +γ k, where α, β and γ are real numbers. If a × b =26 i -11 j -19 k, then α-β+γ is equal to \ \ \ \.

Let $\displaystyle \vec{a}=2 \hat{i}+\alpha \hat{j}+\hat{k}$ and $\displaystyle \vec{b}=\beta \hat{i}-5 \hat{j}+\gamma \hat{k}$, where $\displaystyle \alpha, \beta$ and $\displaystyle \gamma$ are real numbers. If $\displaystyle \vec{a} \times \vec{b}=26 \hat{i}-11 \hat{j}-19 \hat{k}$, then $\displaystyle \alpha-\beta+\gamma$ is equal to \_\_\_\_.
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.