Mathematics · 2024
JEE Main · 4 April 2024, Shift 2 · Q3
Let A= [1, 2; 0, 1] and B=I+ adj (A)+( adj A)^2+…+( adj A)^10. Then, the sum of all the elements of the matrix B is:
Let $\displaystyle A=\left[\begin{array}{ll}1 & 2 \\ 0 & 1\end{array}\right]$ and $\displaystyle B=I+\operatorname{adj}(A)+(\operatorname{adj} A)^2+\ldots+(\operatorname{adj} A)^{10}$.
Then, the sum of all the elements of the matrix B is:
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle -88$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.