Mathematics · 2020
JEE Main · 5 September 2020, Shift 2 · Q71
Let A ={ a, b, c } and B ={1,2,3,4}. Then the number of elements in the set C ={f: A → B ∣ 2 ∈ f( A ) and f is not one-one } is \ \ \ \.
Let $\displaystyle \mathrm{A}=\{\mathrm{a}, \mathrm{b}, \mathrm{c}\}$ and $\displaystyle \mathrm{B}=\{1,2,3,4\}$. Then the number of elements in the set $\displaystyle \mathrm{C}=\{f: \mathrm{A} \rightarrow \mathrm{B} \mid 2 \in f(\mathrm{~A})$ and $\displaystyle f$ is not one-one$\displaystyle \}$ is \_\_\_\_.
Official answer
19
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.