Let a =-5 i + j -3 k, b = i +2 j -4 k and c =((( a × b ) × i ) × i ) × i. Then c ·(- i + j + k ) is equal to:

Let $\displaystyle \overrightarrow{\mathrm{a}}=-5 \hat{i}+\hat{j}-3 \hat{k}, \overrightarrow{\mathrm{~b}}=\hat{i}+2 \hat{j}-4 \hat{k}$ and $\displaystyle \overrightarrow{\mathrm{c}}=(((\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}) \times \hat{i}) \times \hat{i}) \times \hat{i}$. Then $\displaystyle \vec{c} \cdot(-\hat{i}+\hat{j}+\hat{k})$ is equal to: