Mathematics · 2024
JEE Main · 27 January 2024, Shift 2 · Q5
Let α=((4!)!)/((4!)^3!) and β=((5!)!)/((5!)^4!). Then:
Let $\displaystyle \alpha=\frac{(4!)!}{(4!)^{3!}}$ and $\displaystyle \beta=\frac{(5!)!}{(5!)^{4!}}$. Then :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \alpha \in \mathbf{N} \text { and } \beta \in \mathbf{N}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.