Let A= [2, 1, 2; 6, 2, 11; 3, 3, 2] and P= [1, 2, 0; 5, 0, 2; 7, 1, 5]. The sum of the prime factors of |P^-1 A P-2 I| is equal to

Let $\displaystyle A=\left[\begin{array}{ccc}2 & 1 & 2 \\ 6 & 2 & 11 \\ 3 & 3 & 2\end{array}\right]$ and $\displaystyle P=\left[\begin{array}{lll}1 & 2 & 0 \\ 5 & 0 & 2 \\ 7 & 1 & 5\end{array}\right]$. The sum of the prime factors of $\displaystyle \left|P^{-1} A P-2 I\right|$ is equal to