Let | a |=2,| b |=3 and the angle between the vectors a and b be (π)/4. Then |( a +2 b ) ×(2 a -3 b )|^2 is equal to

Let $\displaystyle |\vec{a}|=2,|\vec{b}|=3$ and the angle between the vectors $\displaystyle \vec{a}$ and $\displaystyle \vec{b}$ be $\displaystyle \frac{\pi}{4}$. Then $\displaystyle |(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^2$ is equal to