Let a and b be two vectors such that | a |=√ 14,| b |=√ 6 and | a × b |=√ 48. Then ( a · b )^2 is equal to ____.

Let $\displaystyle \vec{a}$ and $\displaystyle \vec{b}$ be two vectors such that $\displaystyle |\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6}$ and $\displaystyle |\vec{a} \times \vec{b}|=\sqrt{48}$. Then $\displaystyle (\vec{a} \cdot \vec{b})^2$ is equal to $\displaystyle \_\_\_\_$.