Mathematics · 2024
JEE Main · 30 January 2024, Shift 2 · Q18
Let a and b be two vectors such that | b |=1 and | b × a |=2. Then |( b × a )- b |^2 is equal to
Let $\displaystyle \vec{a}$ and $\displaystyle \vec{b}$ be two vectors such that $\displaystyle |\vec{b}|=1$ and $\displaystyle |\vec{b} \times \vec{a}|=2$. Then $\displaystyle |(\vec{b} \times \vec{a})-\vec{b}|^2$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 5$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.