Mathematics · 2021
JEE Main · 26 February 2021, Shift 2 · Q72
Let F_1(A, B, C)=(A ∧ ∼ B) [∼ C ∧(A B)] ∼ A and F_2(A, B)=(A B) (B → ∼ A) be two logical expressions. Then:
Let $\displaystyle F_1(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $\displaystyle F_2(A, B)=(A \vee B) \vee(B \rightarrow \sim A)$ be two logical expressions. Then :
Official answer
(3)
$\displaystyle \mathrm{F}_1$ is not a tautology but $\displaystyle \mathrm{F}_2$ is a tautology
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.