Let E_1 and E_2 be two events such that the conditional probabilities P(E_1 ∣ E_2)=1/2, P ( E_2 ∣ E_1)=3/4 and P ( E_1 ∩ E_2)=1/8. Then:

Let $\displaystyle E_1$ and $\displaystyle E_2$ be two events such that the conditional probabilities $\displaystyle P\left(E_1 \mid E_2\right)=\frac{1}{2}$, $\displaystyle \mathrm{P}\left(\mathrm{E}_2 \mid \mathrm{E}_1\right)=\frac{3}{4}$ and $\displaystyle \mathrm{P}\left(\mathrm{E}_1 \cap \mathrm{E}_2\right)=\frac{1}{8}$. Then :