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Mathematics · 2020

JEE Main · 2 September 2020, Shift 1 · Q75

Let a, b and c be three unit vectors such that | a - b |^2+| a - c |^2=8. Then | a +2 b |^2+| a +2 c |^2 is equal to \ \ \ \.

Let $\displaystyle \vec{a}, \vec{b}$ and $\displaystyle \vec{c}$ be three unit vectors such that $\displaystyle |\vec{a}-\vec{b}|^2+|\vec{a}-\vec{c}|^2=8$. Then $\displaystyle |\overrightarrow{\mathrm{a}}+2 \overrightarrow{\mathrm{~b}}|^2+|\overrightarrow{\mathrm{a}}+2 \overrightarrow{\mathrm{c}}|^2$ is equal to \_\_\_\_.
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.