Mathematics · 2024
JEE Main · 31 January 2024, Shift 2 · Q28
Let A(-2,-1), B(1,0), C(α, β) and D(γ, δ) be the vertices of a parallelogram A B C D. If the point C lies on 2 x-y=5 and the point D lies on 3 x-2…
Let $\displaystyle A(-2,-1), B(1,0), C(\alpha, \beta)$ and $\displaystyle D(\gamma, \delta)$ be the vertices of a parallelogram $\displaystyle A B C D$. If the point $\displaystyle C$ lies on $\displaystyle 2 x-y=5$ and the point $\displaystyle D$ lies on $\displaystyle 3 x-2 y=6$, then the value of $\displaystyle |\alpha+\beta+\gamma+\delta|$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
32
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.