Mathematics · 2019
JEE Main · 12 January 2019, Shift 1 · Q80
Let C_1 and C_2 be the centres of the circles x^2+y^2-2 x-2 y-2=0 and x^2+y^2-6 x-6 y+14=0 respectively. If P and Q are the points of intersection of…
Let $\displaystyle \mathrm{C}_1$ and $\displaystyle \mathrm{C}_2$ be the centres of the circles
$$\begin{aligned}
& x^2+y^2-2 x-2 y-2=0 \text { and } \\
& x^2+y^2-6 x-6 y+14=0 \text { respectively. If } \mathrm{P}
\end{aligned}
$$
and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral $\displaystyle \mathrm{PC}_1 \mathrm{QC}_2$ is :
Official answer
(1)
$\displaystyle 4$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.