Mathematics · 2023
JEE Main · 1 February 2023, Shift 1 · Q90
Let v =α i +2 j -3 k, w =2 α i + j - k and u be a vector such that | u |=α>0. If the minimum value of the scalar triple product [ u v w ] is -α √…
Let $\displaystyle \vec{v}=\alpha \hat{i}+2 \hat{j}-3 \hat{k}, \vec{w}=2 \alpha \hat{i}+\hat{j}-\hat{k}$ and $\displaystyle \vec{u}$ be a vector such that $\displaystyle |\vec{u}|=\alpha>0$. If the minimum value of the scalar triple product $\displaystyle [\vec{u} \vec{v} \vec{w}]$ is $\displaystyle -\alpha \sqrt{3401}$, and $\displaystyle |\vec{u} \cdot \hat{i}|^2=\frac{m}{n}$ where $\displaystyle m$ and $\displaystyle n$ are coprime natural numbers, then $\displaystyle m+n$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
3501
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.