SolveIt is under development
SolveItJEE Main
Mathematics · 2019

JEE Main · 12 April 2019, Shift 1 · Q85

Let a random variable X have a binomial distribution with mean 8 and variance 4. If P ( X ≤ 2)=k/(2^16), then k is equal to:

Let a random variable $\displaystyle X$ have a binomial distribution with mean $\displaystyle 8$ and variance $\displaystyle 4$ .If $\displaystyle \mathrm{P}(\mathrm{X} \leq 2)=\frac{\mathrm{k}}{2^{16}}$, then k is equal to :
ShareWhatsAppTelegram

More from Probability

JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.