Mathematics · 2023
JEE Main · 10 April 2023, Shift 1 · Q29
Let a common tangent to the curves y^2=4 x and (x-4)^2+y^2=16 touch the curves at the points P and Q. Then (P Q)^2 is equal to ____.
Let a common tangent to the curves $\displaystyle y^2=4 x$ and $\displaystyle (x-4)^2+y^2=16$ touch the curves at the points P and Q . Then $\displaystyle (P Q)^2$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
32
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.