Mathematics · 2024
JEE Main · 29 January 2024, Shift 1 · Q4
Let A be a square matrix such that AA^T = I. Then 1/2 A[(A+A^T)^2+(A-A^T)^2] is equal to
Let A be a square matrix such that $\displaystyle \mathrm{AA}^{\mathrm{T}}=\mathrm{I}$. Then $\displaystyle \frac{1}{2} A\left[\left(A+A^T\right)^2+\left(A-A^T\right)^2\right]$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \mathrm{A}^3+\mathrm{A}^{\mathrm{T}}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.