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Mathematics · 2022

JEE Main · 25 June 2022, Shift 1 · Q5

Let A be a 3 × 3 real matrix such that A (1; 1; 0) = (1; 1; 0); A (1; 0; 1) = (-1; 0; 1) and A (0; 0; 1) = (1; 1; 2). If X =(x_1, x_2, x_3)^T and I…

Let A be a $\displaystyle 3$ × $\displaystyle 3$ real matrix such that $\displaystyle \mathrm{A}\left(\begin{array}{l}1 \\ 1 \\ 0\end{array}\right)=\left(\begin{array}{l}1 \\ 1 \\ 0\end{array}\right) ; \mathrm{A}\left(\begin{array}{l}1 \\ 0 \\ 1\end{array}\right)=\left(\begin{array}{c}-1 \\ 0 \\ 1\end{array}\right)$ and $\displaystyle \mathrm{A}\left(\begin{array}{l}0 \\ 0 \\ 1\end{array}\right)=\left(\begin{array}{l}1 \\ 1 \\ 2\end{array}\right)$.If $\displaystyle \mathrm{X}=\left(x_1, x_2, x_3\right)^{\mathrm{T}}$ and I is an identity matrix of order $\displaystyle 3$, then the system $\displaystyle (\mathrm{A}-2 \mathrm{I}) \mathrm{X}=\left(\begin{array}{l}4 \\ 1 \\ 1\end{array}\right)$ has:
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.