Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q64
Let A and B be two invertible matrices of order 3 × 3. If det (A B A^T )=8 and det (A B^-1)=8, then det (B A^-1 B^T) is equal to:
Let A and B be two invertible matrices of order $\displaystyle 3 \times 3$. If $\displaystyle \operatorname{det}\left(A B A^{\mathrm{T}}\right)=8$ and $\displaystyle \operatorname{det}\left(A B^{-1}\right)=8$, then $\displaystyle \operatorname{det}\left(B A^{-1} B^T\right)$ is equal to :
Official answer
(4)
$\displaystyle \frac{1}{16}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.