Let A and B be two events such that P(B ∣ A)=2/5, P(A ∣ B)=1/7 and P(A ∩ B)=1/9. Consider (S1) P(A^′ ∪ B)=5/6, (S2) P(A^′ ∩ B^′)=1/18 Then

Let A and B be two events such that $\displaystyle P(B \mid A)=\frac{2}{5}, P(A \mid B)=\frac{1}{7}$ and $\displaystyle P(A \cap B)=\frac{1}{9}$. Consider (S1) $\displaystyle P\left(A^{\prime} \cup B\right)=\frac{5}{6}$, (S2) $\displaystyle P\left(A^{\prime} \cap B^{\prime}\right)=\frac{1}{18}$ Then