Mathematics · 2023
JEE Main · 31 January 2023, Shift 1 · Q80
( S 1)(p ⇒ q) (p ∧(∼ q)) is a tautology (S2) ((∼ p) ⇒(∼ q)) ∧((∼ p) q) is a contradiction. Then
$\displaystyle (\mathrm{S} 1)(p \Rightarrow q) \vee(p \wedge(\sim q))$ is a tautology
(S2) $\displaystyle ((\sim p) \Rightarrow(\sim q)) \wedge((\sim p) \vee q)$ is a contradiction.
Then
Official answer
From NTA’s final answer key for this paper.
(2)
only (S1) is correct
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.