Mathematics · 2026
JEE Main · 28 January 2026, Shift 1 · Q21
In a G.P., if the product of the first three terms is 27 and the set of all possible values for the sum of its first three terms is R -(a, b), then…
In a G.P., if the product of the first three terms is $\displaystyle 27$ and the set of all possible values for the sum of its first three terms is $\displaystyle \mathbb{R}-(a, b)$, then $\displaystyle a^2+b^2$ is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
90
More from Progressions
- Let a_1, a_2, a_3, …. be an A.P. and g_1=a_1, g_2, g_3, …. be an increasing G.P. If a_1=a_2+g_2=1 and a_3+g_3=4, then a_10+g_5 is equal to:2026
- Let A be the set of first 101 terms of an A.P., whose first term is 1 and the common difference is 5 and let B be the set of first 71 terms of an…2026
- The first term of an A.P. of 30 non-negative terms is 10/3. If the sum of this A.P. is the cube of its last term, then its common difference is:2026
- If Σ_k=1^n a_k=6 n^3, then Σ_k=1^6((a_k+1-a_k)/36)^2 is equal to ____.2026
- Σ_n=1^10(528/(n(n+1)(n+2))) is equal to:2026
- The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the…2026
- Let the sum of the first n terms of an A.P. be 3 n^2+5 n. Then the sum of squares of the first 10 terms of the A.P. is:2026
- The value of 1^3-2^3+3^3-…+15^3 is:2026
JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.