Mathematics · 2025
JEE Main · 2 April 2025, Shift 1 · Q3
If θ ∈[-2 π, 2 π], then the number of solutions of 2 √ 2 cos^2 θ+(2-√ 6 ) cos θ-√ 3 =0, is equal to:
If $\displaystyle \theta \in[-2 \pi, 2 \pi]$, then the number of solutions of $\displaystyle 2 \sqrt{2} \cos ^2 \theta+(2-\sqrt{6}) \cos \theta-\sqrt{3}=0$, is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 8$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.