Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q78
If the two lines x+( a -1) y=1 and 2 x+ a^2 y=1( a ∈ R -{0,1}) are perpendicular, then the distance of their point of intersection from the origin is:
If the two lines $\displaystyle x+(\mathrm{a}-1) y=1$ and $\displaystyle 2 x+\mathrm{a}^2 y=1(\mathrm{a} \in \mathbf{R}-\{0,1\})$ are perpendicular, then the distance of their point of intersection from the origin is :
Official answer
(3)
$\displaystyle \sqrt{\frac{2}{5}}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.