Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q65
If the system of linear equations x+ a y+z=3; x+2 y+2 z=6; x+5 y+3 z= b has no solution, then:
If the system of linear equations
$$\begin{aligned}
& x+\mathrm{a} y+z=3 \\
& x+2 y+2 z=6 \\
& x+5 y+3 z=\mathrm{b}
\end{aligned}
$$
has no solution, then :
Official answer
(2)
$\displaystyle a=-1, b \neq 9$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.