Mathematics · 2021
JEE Main · 4 August 2021, Shift 1 · Q64
If the system of linear equations x+y+z=3; x+b y+b^2 z=7 and a x+a^2 y+a^3 z=1 has infinitely many solutions, then the ordered pair (a, b) is
If the system of linear equations
$$\begin{aligned}
& x+y+z=3 \\
& x+b y+b^2 z=7 \\
\text { and } \quad & a x+a^2 y+a^3 z=1
\end{aligned}
$$
has infinitely many solutions, then the ordered pair $\displaystyle (a, b)$ is
Official answer
(4)
$\displaystyle \left(\frac{1}{7}, \frac{1}{7}\right)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.