Mathematics · 2019
JEE Main · 8 April 2019, Shift 2 · Q65
If the system of linear equations x-2 y+k z=1; 2 x+y+z=2; 3 x-y-k z=3 has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose…
If the system of linear equations
$$\begin{aligned}
& x-2 y+k z=1 \\
& 2 x+y+z=2 \\
& 3 x-y-k z=3
\end{aligned}
$$
has a solution $\displaystyle (x, y, z), z \neq 0$, then $\displaystyle (x, y)$ lies on the straight line whose equation is:
Official answer
(4)
$\displaystyle 4 x-3 y-4=0$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.