Offline paper
Mathematics · 2018
JEE Main 2018 · 2018-04-08 Offline · Q65
If the system of linear equations x+ k y+3 z=0; 3 x+ k y-2 z=0; 2 x+4 y-3 z=0 has a non-zero solution (x, y, z), then (x z)/y^2 is equal to:
If the system of linear equations
$$\begin{array}{r}
x+\mathrm{k} y+3 z=0 \\
3 x+\mathrm{k} y-2 z=0 \\
2 x+4 y-3 z=0
\end{array}
$$
has a non-zero solution $\displaystyle (x, y, z)$, then $\displaystyle \frac{x z}{y^2}$ is equal to :
Official answer
(2)
$\displaystyle 10$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.