Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q54
If the system of equations x+y+z=2; 2 x+4 y-z=6; 3 x+2 y+λ z=μ has infinitely many solutions, then:
If the system of equations
$$\begin{aligned}
& x+y+z=2 \\
& 2 x+4 y-z=6 \\
& 3 x+2 y+\lambda z=\mu
\end{aligned}
$$
has infinitely many solutions, then :
Official answer
(4)
$\displaystyle 2 \lambda+\mu=14$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.