Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q65
If the system of equations 2 x+3 y-z=0, x+ k y-2 z=0 and 2 x-y+z=0 has a non-trivial solution ( x, y, z ), then x/y+y/z+z/x+k is equal to:
If the system of equations $\displaystyle 2 x+3 y-z=0$, $\displaystyle x+\mathrm{k} y-2 z=0$ and $\displaystyle 2 x-y+z=0$ has a non-trivial solution ( $\displaystyle x, y, z$ ), then $\displaystyle \frac{x}{y}+\frac{y}{z}+\frac{z}{x}+k$ is equal to :
Official answer
(4)
$\displaystyle \frac{1}{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.